Nad RS 232 Article
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RS-2 32 P ro to co l f o r N AD P ro ducts v 1 .0 3 Page 2 o f 3 S in ce t h e c o ntr o l c h ara cte rs a re s im ply s e n t a s s in gle b yte v alu es, t h ere n eed s t o b e a w ay t o d if fe re n tia te b etw ee n a c o ntr o l c h ara cte r a n d r e g ula r d ata . A s ta n d ard w ay o f d oin g t h is , w hic h t h is p ro to co l u se s, i s t o u se a fla g c h ara cte r ( w hic h i s a c o ntr o l c h ara cte r) t o e n co de t h e r e g ula r d ata w hic h h av e t h e s a m e v alu e a s a c o ntr o l c h ara cte r. B efo re d esc rib in g h o w t h e d ata i s e n co ded , t h e c o ntr o l c h ara cte rs w ill b e l is te d s o t h ey c an b e u se d i n e x am ple s. T he f o llo w in g t a b le s h o w s a ll t h e c o ntr o l c h ara cte rs a n d t h eir c o rre sp ond in g v alu es: Contr o l C hara cte r Valu e < sta rt> 1 < ch eck su m > 2 R ese rv ed f o r F utu re E xp an sio n 0, 3 – 1 9 < fla g > 94 C ontr o l c h ara cte rs 0 a n d 4 t h ro ug h 1 9 h av e b een r e se rv ed f o r f u tu re e x p an sio n. F or e x am ple , s ta n d ard X ON/X OFF f lo w c o ntr o l u se s c h ara cte rs 1 7 a n d 1 9. A ny d ata v alu es w hic h a re t o b e s e n t t h at c o rre sp ond t o a c o ntr o l c h ara cte r m ust b e e n co ded w it h t h e f o llo w in g m eth o d: 1 . Sen d t h e f la g c o ntr o l c h ara cte r. 2 . Sen d t h e d ata v alu e b it w is e O Red w ith t h e v alu e 6 4. A ll o th er d ata v alu es w hic h d o n o t c o rre sp ond t o a c o ntr o l c h ara cte r c an b e s e n t a s i s . S om e e x am ple s: Data V alu e t o S en d Enco ded b yte s e q uen ce 3 94, 6 7 5 94, 6 9 2 0 20 9 4 94, 9 4 O n t h e r e ceiv in g s id e, a n yti m e a v alu e o f 9 4 i s r e ceiv ed t h e f o llo w in g c h ara cte r m ust b e d eco ded . T he c h ara cte r i s d eco ded u sin g t h e f o llo w in g a lg o rith m : 1 . If t h e v alu e r e ceiv ed i s 9 4, t h en t h e a ctu al v alu e i s 9 4. 2 . Els e , t h e r e ceiv ed v alu e s h o uld b e b itw is e A N Ded w it h t h e v alu e 1 91. F or e x am ple , i f t h e s e q uen ce 9 4, 6 9 i s r e ceiv ed , i t s h o uld b e d eco ded t o t h e v alu e 5 s in ce 6 9 A N D 1 91 e q uals 5 . C hecksu m C alc u la tio ns The c h eck su m i s s im ply t h e i n vers e ( o nes c o m ple m en t) o f t h e s u m o f t h e C om man d a n d D ata b yte s o f t h e p ack et. F or e x am ple , i f t h e c o m man d b yte w as 2 0, a n d t h e d ata b yte w as 2 0, t h en t h e c h ec k su m w ould b e 2 15. ( 2 0 + 2 0 = 4 0, c o m ple m en t o f 4 0 = 2 15). W hen t h e d ata v alu es a re e n co ded b ecau se t h ey o verla p w it h a c o ntr o l c h ara cte r, t h e a ctu al v alu e s h o uld b e u se d i n t h e s u m a n d n o t t h e e n co ded v alu e.
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RS-2 32 P ro to co l f o r N AD P ro ducts v 1 .0 3 Page 3 o f 3
C om man d S et
T he c o m man d s e t i s d ocu m en te d i n s e v era l t a b le s i n a s e p ara te d ocu m en t. I t d esc rib es w hat a ll t h e
c o m man d s a re a n d w hic h p ro ducts s u p port w hic h c o m man d s.
A dditio ns t o t h e c o m man d s e t w il l b e d one o n a n o ngo in g b asis a s n ew f u nctio ns a re n eed ed f o r n ew
p ro ducts .
E xam ple 1
This e x am ple w ill d esc rib e e x actl y w hat i s s e n t w hen t h e I d en ti f ic atio n o f t h e u nit i s Q uerie d . T his i s d one
b y s e n d in g t h e Q uery F unctio n c o m man d w hic h i s c o m man d 2 0. S in ce i t i s t h e I d en ti f ic atio n t h at i s b ein g
q uerie d , t h e d ata v alu e 2 0 i s s e n t w it h t h e c o m man d .
T he a b ove i s d one b y s e n d in g t h e f o llo w in g b yte s e q uen ce:
< sta rt> Com man d Data